Question

Two very small +3.00-μC charges are at the ends of a meter stick. Find the electric potential (relative to infinity) at the center of the meter stick.

Answer 1

The electric potential at the center of the meter stick is 54 KV.

Step-by-step explanation:

Electric potential (V) is given as:

i.e V =
`(kq)/(r)`

Where: k is the Coulomb constant, q is the charge and r is the distance.

Given: q = 3.0 μC = 3.0 x
`10^(-6)` C, r = 0.5 m

So that,

V =
`(9*10^(9)*3.0*10^(-6) )/(0.5)`

=
`(2.7*10^(4) )/(0.5)`

V = 54000

= 54 000 volts

The electric potential at the center of the meter stick is 54 KV.