Question

Simplify this Boolean algebra
AB'C+A'B'C+ABC+A'BC'​

Answer 1

Explanation:

To simplify the given Boolean algebra expression, we can use Boolean algebra rules such as De Morgan's laws, distributive law, and complementation law.

Let's simplify step by step:

1. Apply De Morgan's law to the third term (ABC):

ABC = (A' + B' + C')

2. Apply the distributive law to the first and second terms:

AB'C + A'B'C = (A + A')B'C

3. Simplify the expression:

(A + A')B'C = 1B'C = B'C

4. Apply the distributive law to the result from step 3 and the third term:

B'C + (A'BC') = B'C + (A' + B' + C')

5. Simplify the expression:

B'C + (A' + B' + C') = B'C + 1 = B'C

Therefore, the simplified form of the Boolean algebra expression AB'C + A'B'C + ABC + A'BC' is B'C.