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A beam of electrons accelerated in an electric field is passing through two slits separated by a very small distance d and then hits a screen that glows when an electron hits it. The potential difference is v. Assume the distance from the slits to the screen is l.

User Amandeep
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Final answer:

In this experiment, a beam of electrons accelerated in an electric field passes through two slits and hits a screen. The behavior of electrons can be explained by their wave-particle duality. To calculate the potential difference traveled by an electron, use the equation qV = 1/2 mv^2.

Step-by-step explanation:

In this experiment, a beam of electrons is accelerated in an electric field and passes through two slits separated by a small distance d before hitting a screen. The potential difference is v and the distance from the slits to the screen is l. The behavior of electrons in this experiment can be explained by their wave-particle duality.

When the slits are relatively large, the electrons behave like particles and create two bands of hits on the screen. However, if the slits are small and close together, the electrons diffract and interfere with each other, creating an interference pattern similar to light waves. To calculate the potential difference traveled by an electron, we need to use the equation qV = 1/2 mv^2, where q is the charge of the electron, V is the potential difference, m is the mass of the electron, and v is the final velocity of the electron. Plugging in the given values, we can calculate the potential difference.

User Ashley Alvarado
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