Question

Correct the following python code to return with no errors:

Prompt:
Assume you were given the following data about student grades in a class. After the student’s name, the 9 inputs are the grades for that class. All the grades are equally weighted. The data is provided at runtime as sys.argv.
Dawn 74 75 83 75 78 84 68 72 84
Lindsey 86 95 75 85 63 84 75 0 81
Here is what I would type in command prompt for the above example:
python test2-4.py Dawn 74 75 83 75 78 84 68 72 84
python test2-4.py Lindsey 86 95 75 85 63 84 75 0 81
Write a script called test2-4.py that calls a function called calc_avg( ) to calculate a student’s class average.
You must use a loop to process through the grades to calculate the average. There will be no credit unless you do use a loop and no credit if you use a list.
You can assume that the input is always valid (no one is going to type a negative number or a string like "cat").
You can also assume that the number of arguments provided is always correct.
Use the round()function to have only 1 decimal place in the answer.
The output for the above input should exactly match the following:
Dawn’s average is 77.0.
Lindsey’s average is 71.6.
Script:
import sys
def calc_avg(grades):
sum = 0
for i in range(9):
sum += int(grades[i+1])
avg = sum / 9
avg = round(avg, 1)
return avg
name = sys.argv[1]
grades = sys.argv
avg = calc_avg(grades)
print(str(name)+"'s average is "+str(avg)+".")
Error:
C:\Users >python "C:\Users' \IT2430\Test 2\test2-4.py" Dawn 74 75 83 75 78 84 68 72 84 Traceback (most recent call last):
File "C:\Users\ AIT2430\Test 2\test2-4.py", line 18, in
avg = calc_avg(grades)
File "C:\Users\ IT2430\Test 2\test2-4.py", line 10, in calc_avg
sum += int(grades [i+1])
ValueError: invalid literal for int() with base 10: 'Dawn

Answer 1

To fix the Python script, the 'calc_avg' function should be modified to skip the first command line argument, which is the student's name, when summing grades.

The code provided above does that correctly and calculates the average of the grades, rounding it to one decimal place.

Step-by-step explanation:

The Python script provided has a ValueError because it is trying to convert the student's name ('Dawn' or 'Lindsey') to an integer, which is not possible. The calc_avg function should start summing grades from the second argument (index 1) since the first argument (index 0) is the student's name. Below is the corrected version of the script:

import sys
def calc_avg(grades):
sum = 0
for grade in grades[1:]: # Start from index 1 to skip the name
sum += int(grade)
avg = sum / (len(grades) - 1) # Subtract 1 for the name
return round(avg, 1)

name = sys.argv[1]
avg = calc_avg(sys.argv[1:]) # Pass only the grades to the function
print(f"{name}'s average is {avg}.")

This code properly calculates the average grade and rounds it to one decimal place. It is expected to run without errors when provided with the correct command line arguments.