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14 votes
-3(2x + 2) < 10

and

2(4 - 2x) > 1

pre calculus

User Lepanto
by
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1 Answer

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\\ \tt\hookrightarrow -3(2x+2)<10


\\ \tt\hookrightarrow -6x-6<10


\\ \tt\hookrightarrow -6x<16


\\ \tt\hookrightarrow x>-16/6


\\ \tt\hookrightarrow x>-8/3

And


\\ \tt\hookrightarrow 2(4-2x)>1


\\ \tt\hookrightarrow 8-4x>1


\\ \tt\hookrightarrow -4x>-7


\\ \tt\hookrightarrow 4x<7


\\ \tt\hookrightarrow x<7/4

So


\\ \tt\hookrightarrow x\in \left((-8)/(3),(7)/(4)\right)

User Alex Collins
by
8.6k points

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