Question

What does each removeMin call return within the following sequence of priority queue ADT operations: insert(5, A), insert(4, B), insert(7, F), insert(1, D), removeMin(), insert(3, J), insert(6, L), removeMin(), removeMin( ),insert(8,G), removeMin( ),insert(2,H), removeMin( ), removeMin( ), removeMin( )

Answer 1

The removeMin() operation in a priority queue ADT returns the minimum element and removes it from the queue. The given sequence of operations returns the minimum elements in the priority queue.

Step-by-step explanation:

The removeMin() operation in a priority queue ADT returns the minimum element in the priority queue and removes it from the queue. Let's go through the given sequence of operations to determine what each removeMin() call returns:

1. In the initial state, the minimum element is 1, so the first removeMin() call returns 1.
2. After inserting 3, 4, 5, 6, and 7, the minimum element is still 1, so the next removeMin() call also returns 1.
3. After inserting 8, the minimum element becomes 2, so the third removeMin() call returns 2.
4. The final removeMin() calls return the remaining elements in ascending order: 3, 4, 5, 6, 7, and 8.

Therefore, the sequence of removeMin() calls returns: 1, 1, 2, 3, 4, 5, 6, 7, 8.