Question

Show how the value 0xF0F1F2F3 would be arranged in memory of a

little-endian and a big-endian machine. Assume
the data are stored starting at address 0x00001000 and that the
word size is 4 bytes.

Answer 1

The value 0xF0F1F2F3 is arranged differently in memory based on whether it's a little-endian or big-endian machine. In a little-endian machine, the least significant byte comes first, while in a big-endian machine, the most significant byte comes first.

Step-by-step explanation:

In a little-endian machine, the value 0xF0F1F2F3 would be arranged in memory as follows:

Address 0x00001000: F3

Address 0x00001001: F2

Address 0x00001002: F1

Address 0x00001003: F0

This is because in a little-endian system, the least significant byte is stored first at the lowest memory address.

In a big-endian machine, the value 0xF0F1F2F3 would be arranged in memory as follows:

Address 0x00001000: F0

Address 0x00001001: F1

Address 0x00001002: F2

Address 0x00001003: F3

In a big-endian system, the most significant byte is stored first at the lowest memory address.