Final answer:
The statement 'f(n)=O(g(n)) implies g(n)=Ω(f(n))' is false.
Step-by-step explanation:
The statement 'f(n)=O(g(n)) implies g(n)=Ω(f(n))' is false.
Big O notation and Big Omega notation are used to describe the upper and lower bounds of a function, respectively.
If f(n) = O(g(n)), it means that g(n) grows at least as fast as f(n) or faster. However, it does not guarantee that g(n) is the tightest lower bound for f(n). Therefore, g(n) may not be Ω(f(n)).