Question

Please answer in detail: How exactly would i go about creating this array in mips assembly and storing each of these specific numbers in the list how i then proceed to create a size of function in mips for the second line? int arr[] = {7, 9, 4, 3, 8, 1, 6, 2, 5}; int n = sizeof(arr) / sizeof(arr[0]);

Answer 1

To create an array in MIPS assembly, use the `.data` section, and to calculate the size of the array, use the `sizeof` operator divided by the `sizeof` of an individual element.

Step-by-step explanation:

To create an array in MIPS assembly and store specific numbers, you would need to use the .data section to define the array and initialize it with the desired values. Here's an example:

.data
arr: .word 7, 9, 4, 3, 8, 1, 6, 2, 5

To calculate the size of the array, you can use the formula: size = sizeof(arr) / sizeof(arr[0]). This can be done using the la (load address) and li (load immediate) instructions. Here's how:

la $t0, arr
li $t1, 4
li $t2, 9
mul $t3, $t1, $t2

Now, the value of $t3 will hold the size of the array.