57.3k views
4 votes
Consider the following assembly code segment below:

LDRB R1, [R0, #0x00]
AND R1, #0x10
CMP R1, #0x10
In this code segment above, assume you are loading the byte from an input register for a given port. Why are you using an AND operation with the input register byte?

1 Answer

1 vote

Final answer:

The AND operation is used to mask the byte and isolate the 5th bit, which can then be checked to determine whether it is set or not. This is common in embedded systems to check specific bit fields within an input register.

Step-by-step explanation:

You are using an AND operation with the input register byte to mask the contents of the register and isolate a specific bit or set of bits. In this particular case, the AND operation with #0x10 (which in binary is 00010000) is used to check the status of the 5th bit in the byte loaded into R1. If after the operation the result in R1 is #0x10, it means the 5th bit was set (1).

The CMP instruction is then used to compare the result of the AND operation to #0x10 itself. If the comparison is equal, this implies that the 5th bit in the byte at the address pointed to by R0 was indeed set. Such a technique is commonly used in embedded systems programming to check the status of pins, flags, or other specific bit fields within an input register.

The AND operation is used in this code segment to check if a specific bit of the input register byte is set or not. The value 0x10 represents a bitmask with the 5th bit set and all other bits cleared. By performing the AND operation, the result will be a non-zero value if the 5th bit of the input register byte is set. If the result is zero, it means the 5th bit is not set.

User Adam LeBlanc
by
7.8k points