Final answer:
There are 23.1 grams of calcium in 45.0 grams of calcium fluoride, determined by calculating the molar mass of CaF2 and using it to find the proportional mass of calcium within the compound.
Step-by-step explanation:
To find out how much calcium is contained in 45.0 g of calcium fluoride (CaF2), first, we need to calculate the molar mass of CaF2. The atomic mass of calcium (Ca) is approximately 40.08 amu, and the atomic mass of fluorine (F) is about 19.00 amu. Therefore, the molar mass of CaF2 is (40.08 amu for Ca) + (2 × 19.00 amu for F) = 78.08 amu.
We can set up a proportion to find the mass of calcium in the 45.0 g of CaF2 using the molar masses:
- (40.08 g Ca / 78.08 g CaF2) = (x g Ca / 45.0 g CaF2)
By cross-multiplying and solving for x:
x = (40.08 g Ca / 78.08 g CaF2) × 45.0 g CaF2 = 23.1 g Ca
Therefore, there are 23.1 grams of calcium in 45.0 grams of calcium fluoride.