Answer:
i. P = -800t + 29900
ii. as an inequality: 0≤t≤37.375; interval notation: [0,37.375]
iii. as an inequality: 0≥P≥29900; interval notation: [0,29900]
iv. the population decreases at a rate of 1600 people every 3 years
v. 2010
Explanation:
i. a) use the points *(4,26700) and **(12,20300) to find the slope (m)
*: the year 1995(4 years after 1991) and the population that year
**: the year 2003(12 years after 1991) and the population that year
m = (20300-26700)/(12-4) = -6400/8 = -800
b) use one of the points and m in (a) to find b
26700 = -800(4) + b
26700 = -3200 + b
29900 = b
ii. starting value for domain will be 0 since 1991 is year 0. Find the ending domain value by using P=0 and solving the equation for t:
0 = -800t + 29900
800t = 29900
t = 37.375
iii. population starts at a high of 29900 people and can't go lower than 0 people.
iv. the slope is given in (population change) / (number of years)
v. make P=14700 and solve the equation for t
14700 = -800t + 29900
800t = 15200
t = 19 (19 years after 1991)