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What is the value of variable num after execution.

int number = 10;
num += 100;
num -= 20;
printf("%d",num);

1 Answer

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Final answer:

The value of the variable num when executing printf("%d",num); cannot be determined without additional context. The printf function prints the value of num as a decimal integer, but the actual value depends on prior code that initializes or modifies num.

Step-by-step explanation:

To accurately determine the value of the variable num after the execution of the printf("%d",num); statement, additional information is required. Specifically, we need to know how the variable num is initialized and altered before this statement executes. The printf function is part of the C programming language standard input/output library functions and is used for formatted output to the screen. In this case, printf("%d",num); will print the value of num as a decimal integer.

Without context or preceding code, we can't specify the value of num since it is determined by prior operations in the program. If no value has been assigned to num, the printed result can be unpredictable because num will contain whatever value happens to be at the memory location assigned to it, which is referred to as 'garbage value'.

In conclusion, to know the value of num at the time printf is called, we must look at the program code preceding this statement for assignments or modifications to num. Without this context, we cannot provide a definite value.

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