Question

1: Identify the errors in this code.

2: Fix the code so that it works.
x = 10
def foo( ):
z = 10
x = 20
foo( )
print(z)

Answer 1

The code contains errors in the variable 'z' and in calling the 'foo' function. The code can be fixed by defining 'z' outside of the function and calling the 'foo' function before printing 'z'.

Step-by-step explanation:

The code contains a few errors:

1. The variable 'z' is defined inside the 'foo' function, so it is not accessible outside of the function. Trying to print 'z' will result in an error.

2. The function 'foo' is not called before trying to print 'z'. This means that the 'x' variable inside 'foo' is not assigned a value and the function does not execute.

To fix the code, you can define 'z' outside of the 'foo' function and call the 'foo' function before trying to print 'z'. Here's the corrected code:

x = 10
z = 0
def foo():
global z
z = 10

def bar():
x = 20
foo()

bar()
print(z)

Now the code will first call the 'bar' function which assigns a value of 20 to 'x' and then calls the 'foo' function which assigns a value of 10 to 'z'. Finally, 'z' is printed and the output will be 10.