Question

In Java, please develop a program. The program shows a O(n*logn) time complexity. You may design nested loops. When you input a number, the output should be how many times of the loops. For example, if your input is 10, the number of loops should be 30 times, 60 times, etc. The number of loops do not have to be an accurate number

Answer 1

In Java, you can achieve a time complexity of O(n*logn) by using nested loops to sort an array of elements. One way to do this is by using a divide and conquer algorithm like Merge Sort.

Step-by-step explanation:

In Java, you can achieve a time complexity of O(n*logn) by using nested loops to sort an array of elements. One way to do this is by using a divide and conquer algorithm like Merge Sort, which has a time complexity of O(n*logn).

Here is an example of how you can implement a Merge Sort algorithm in Java:

1. Split the array into two halves.
2. Sort each half recursively using Merge Sort.
3. Merge the two sorted halves into a single sorted array.

When you input a number into the program, the number of loops required will depend on the size of the array. For example, if the input is 10, the number of loops would be:

30 times for splitting the array into halves (log2 10 = 3),

60 times for sorting each half (3 * 10 = 30), and

30 times for merging the sorted halves.