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at a given temperature, the vapor pressures of hexane and toluene are 183 mm hg and 59.2 mm hg, respectively. calculate the total vapor pressure over a solution of hexane and toluene. the mole fraction of hexane (x hexane) is 0.520.

User Mikael Engver
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2 Answers

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answer is in th epic

at a given temperature, the vapor pressures of hexane and toluene are 183 mm hg and-example-1
User Grigor Yosifov
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12 votes
12 votes

Answer:

total of 131 millimeters of mercury

Step-by-step explanation:

So we can calculate the total vapour pressure using the equation. The total pressure p equals x a where x is the mole fraction of a and the p a is the partial pressure of a plus x b being the mule fraction of b and the partial pressure of b we can get the mule fraction of a and B because 1 will equal x, a plus x b and a is hexane and b is octane, and so the mole fraction of hexane is 1.580, and so we can set this up to solve. As x b will equal 1 minus x a which is equal to 1 minus .58, which is equal to .4 2 point now, because we have all our numbers, we can put them into our full equation. So we have. The pressure is equal to .58 times. The pressure of our hexane, which is greater than 183, and this has added 2.42 and the pressure of our octane, which is 59.2, and so we get a total of 131 millimeters of mercury. As our total vapour pressure.

User Erbsock
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