Question

What will be the output of the program?

#include
int main() (
float a=0.7;
if(a < 0.7)
printf(C );
else
printf(C++ );
return 0;
)

a) C
b) C++
c) Neither C nor C++
d) Compiler error

Answer 1

The program compares a float variable 'a' with the double precision literal 0.7, and due to floating-point representation, it may lead to the true condition in the 'if' statement, resulting in the output 'C'.

Step-by-step explanation:

The question involves an exploration of floating-point comparison in the C programming language. Here's how the provided code works:

• A float variable a is declared and initialized to 0.7.
• The if statement checks if a is less than 0.7. However, due to floating-point representation, the value of a in memory may be slightly less than 0.7 when stored as a float.
• Since literal 0.7 is treated as double precision by default, the comparison is between a float and a double, potentially leading to a true condition.
• As a result, the printf function will print C, as a is found to be less than 0.7 in this context.

The correct answer is a) C, since the program will execute the first branch of the if statement.