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What is the equation representing the height (h) of an object thrown up at an initial velocity of 16ft/sec?

a) h=16t−16t²
b) h=16t+16t²
c) h=16t²−16t
d) h=16−16t²

User Cristhiank
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Final answer:

The correct equation representing the height of an object thrown upward at an initial velocity of 16ft/sec is a) h = 16t - 16t², adjusting the kinematic formula h = v0t - ½gt² for gravity.

Step-by-step explanation:

The equation representing the height (h) of an object thrown upward at an initial velocity can be derived from the kinematic equations for uniformly accelerated motion. The general form of this equation is h = v0t - ½gt², where h is the height, v0 is the initial velocity, t is the time, and g is the acceleration due to gravity. For an object thrown up at an initial velocity of 16ft/sec and assuming down is positive, we'll adjust the formula to h = 16t - ½(32)t² (since g = 32ft/s² for gravity), simplifying this equation, we get h = 16t - 16t². Therefore, the correct equation that represents the height of the object is a) h = 16t - 16t².

User Domshyra
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