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10 votes
2^2/5+ 3^1/10
HELP ASAP

User Cassi
by
7.3k points

1 Answer

10 votes

Answer:


\sqrt[5]{4} +
\sqrt[10]{3}

Explanation:

We sure can write 2^2/5+ 3^1/10 as
2^{(2)/(5) } + 3^{(1)/(10) }

// use the
a^{(m)/(n) } =\sqrt[n]{a^(m) } to transform the expression

Convert
2^{(2)/(5) } to
\sqrt[5]{2^(2) } =
\sqrt[5]{4} (here a = 2, n = 5, m = 2)

Then convert
3^{(1)/(10) } to
\sqrt[10]{3^(1) } =
\sqrt[10]{3} (here a = 3, n = 10, m = 1)

Now we get
2^{(2)/(5) } + 3^{(1)/(10) } =
\sqrt[5]{4} +
\sqrt[10]{3} . This is the simplified form, which is the answer.

User Djeeg
by
6.2k points
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