Question

2^2/5+ 3^1/10
HELP ASAP

Answer 1

`\sqrt[5]{4}` +
`\sqrt[10]{3}`

Explanation:

We sure can write 2^2/5+ 3^1/10 as
`2^{(2)/(5) } + 3^{(1)/(10) }`

// use the
`a^{(m)/(n) } =\sqrt[n]{a^(m) }` to transform the expression

Convert
`2^{(2)/(5) }` to
`\sqrt[5]{2^(2) }` =
`\sqrt[5]{4}` (here a = 2, n = 5, m = 2)

Then convert
`3^{(1)/(10) }` to
`\sqrt[10]{3^(1) }` =
`\sqrt[10]{3}` (here a = 3, n = 10, m = 1)

Now we get
`2^{(2)/(5) } + 3^{(1)/(10) }` =
`\sqrt[5]{4}` +
`\sqrt[10]{3}` . This is the simplified form, which is the answer.