Question

The pressure in a can of hairspray is 2.50 atm at 298 K. What is the volume in the can when it contains 2.00 moles of gas inside?

a) 1.20 L
b) 2.50 L
c) 3.00 L
d) 5.00 L

Answer 1

The volume of the can when it contains 2.00 moles of gas inside is approximately 1.94 L.

Step-by-step explanation:

To find the volume of the can, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Rearranging the equation to solve for V, we get V = nRT/P.

Given that the pressure (P) is 2.50 atm, the number of moles (n) is 2.00, and the temperature (T) is 298 K, we can plug in these values to find the volume (V).

V = (2.00 mol * 0.0821 L*atm/(mol*K) * 298 K) / 2.50 atm = 1.94 L

Therefore, the volume in the can when it contains 2.00 moles of gas inside is approximately 1.94 L.