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(-7)^5/3 x (1/56)^5/3 Evaluate

User Zihotki
by
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2 Answers

5 votes

The value of expression
$$(-7)^{(5)/(3)}\cdot((1)/(56))^{(5)/(3)
$$(-7)^{(5)/(3)}\cdot((1)/(56))^{(5)/(3) is
-(1)/(32)$$.

Let's evaluate the expression in the image:


$$(-7)^{(5)/(3)}\cdot((1)/(56))^{(5)/(3)}$$

We can simplify the expression using the following properties of exponents:


$x^m \cdot x^n = x^(m+n)$


$\left((x)/(y)\right)^m = (x^m)/(y^m)$

Simplify the expression:


$$(-7)^{(5)/(3)}\cdot((1)/(56))^{(5)/(3)} = (-7)^{(5)/(3)}\cdot((1)/(2^3 \cdot 7))^{(5)/(3)}$$


$$= (-7)^{(5)/(3)}\cdot(2^(-3) \cdot 7^(-1))^{(5)/(3)}$$

Apply the exponent properties:


$$= (-7)^{(5)/(3)}\cdot 2^{(-3)\cdot(5)/(3)}\cdot 7^{(-1)\cdot(5)/(3)}$$


$$= -7^{(5)/(3)}\cdot 2^(-5)\cdot 7^{-(5)/(3)}$$

Simplify further:


$$= (-1 \cdot 7)^{(5)/(3)}\cdot 2^(-5)\cdot 7^{-(5)/(3)}$$


$$= -1\cdot 7^{(5)/(3)}\cdot 2^(-5)\cdot 7^{-(5)/(3)}$$


$$= -1\cdot 7^{{(5)/(3)}-{(5)/(3)}}\cdot 2^(-5)$$


$$= -1\cdot 1\cdot 2^(-5)$$


$$= -2^(-5)$$

Convert negative power to positive:


$$= -(1)/(2^(5))$$

Calculate the final answer:


$$= -(1)/(32)$$

User MpSchrader
by
8.8k points
2 votes

Final answer:

To evaluate the expression (-7)^5/3 x (1/56)^5/3, break the expression down, apply the exponent to both -7 and 1/56, and finally express the negative result in proper scientific notation.

Step-by-step explanation:

The question involves evaluating the expression (-7)5/3 × (1/56)5/3. To solve this, you must first break it down into two parts: raising -7 and 1/56 each to the power of 5/3. To raise a negative number to an odd fractional exponent, the result is negative. For 1/56, you will raise both numerator and denominator to the 5/3 power. After computing, both results will be multiplied together.

Since both the constants -7 and 56 have the same exponent, we can combine them under a single exponent like this: ((-7)/56)5/3. You would then calculate by raising -1/8 to the power of 5/3, which simplifies the computation. The final answer can be expressed in proper scientific notation, with a sign to indicate it is a negative result.

User Valeklosse
by
7.4k points

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