Question

A golf ball is launched upward with an initial speed of 30m/s by a golfer on the third level of The Golf Club at Chelsea Piers, Manhattan, which is 10m above the ground. How high above the ground will the ball be after 3sec?

a. 45 m
b. 30 m
c. 20 m
d. 15 m

Answer 1

The golf ball will be 45m above the ground after 3 seconds.

Step-by-step explanation:

To find how high above the ground the golf ball will be after 3 seconds, we can use the equation for the height of a projectile:

h = h0 + v0t - (1/2)gt^2

where h is the final height, h0 is the initial height, v0 is the initial vertical velocity, t is the time, and g is the acceleration due to gravity.

In this case, h0 is 10m, v0 is 30m/s, t is 3s, and g is approximately 9.8m/s^2. Plugging in these values, we get:

h = 10 + (30)(3) - (1/2)(9.8)(3)^2 = 45m

So the correct answer is 45m.