Question

A lift of mass 2000 kg, when it goes upward with a uniform speed of 3 m/s, then a friction force of 4000 N acts on it. What is the horsepower of the motor that should be used to move the lift upward?

a) 1 HP
b) 2 HP
c) 3 HP
d) 4 HP

Answer 1

To determine the horsepower of the motor that should be used to move the lift upward against a friction force, calculate the power required using the formula Power = Force × Velocity. Convert the power to horsepower by dividing by 746 W/hp. The horsepower of the motor should be approximately 16.07 HP.

Step-by-step explanation:

To determine the horsepower of the motor that should be used to move the lift upward, we need to calculate the power required to overcome the friction force. Power is given by the equation:

Power = Force × Velocity

Plugging in the values, we get:

Power = 4000 N × 3 m/s

Power = 12000 W

Converting to horsepower, 1 hp is equal to 746 W, so:

Power = 12000 W ÷ 746 W/hp

Power = 16.07 hp

Therefore, the horsepower of the motor should be approximately 16.07 HP.