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13 votes
Question:

What are the solutions to 3x^2 + 12x + 6 = 0?

Hint::
use the quadratic formula

User Huddds
by
3.0k points

1 Answer

3 votes

Answer:

x₁ = - 2 + √2 , x₂ = - 2 - √2

Explanation:


3x^2 + 12x + 6 = 0\\\\a=3\,,\ b=12\,,\ c=6\\\\\\ x=(-b\pm√(b^2-4ac))/(2a)\\\\ x=(-12\pm√(12^2-4\cdot3\cdot6))/(2\cdot3)=(-12\pm√(144-72))/(2\cdot3)=(-12\pm√(72))/(2\cdot3)=(-12\pm6√(2))/(6)\\\\x_1=(6(-2+√(2)))/(6)=-2+\sqrt2\\\\x_2=(6(-2-√(2)))/(6)=-2-\sqrt2

User Dzintars
by
3.6k points