Question

Calculate the wavelength of light emitted by an electron in hydrogen as it moves from (n = 6) to (n = 3).

(Given: Speed of light, (c = 3.00 times 10^8 m/s); Planck's constant, (h = 6.63 times 10^(-34) J.s); Rydberg's constant, (R_h = 2.18 times 10^(-18)j))

Answer 1

To calculate the wavelength of light emitted by an electron in hydrogen as it moves from (n = 6) to (n = 3), we can use the Rydberg formula.

Step-by-step explanation:

To calculate the wavelength of light emitted by an electron in hydrogen as it moves from (n = 6) to (n = 3), we can use the Rydberg formula:

1/λ = Rh * (1/n12 - 1/n22)

Where λ is the wavelength, Rh is the Rydberg's constant, n1 is the initial energy level, and n2 is the final energy level.

Plugging in the values:

1. 1/λ = (2.18 x 10-18 J) * (1/62 - 1/32)
2. 1/λ = (2.18 x 10-18 J) * (1/36 - 1/9)
3. 1/λ = (2.18 x 10-18 J) * (1/36 - 4/36)
4. 1/λ = (2.18 x 10-18 J) * (1 - 4)/36
5. 1/λ = (2.18 x 10-18 J) * (-3)/36
6. 1/λ = (-2.18 x 10-18 J) / 12
7. 1/λ = -1.82 x 10-19 J
8. λ = -5.49 x 1018 m

The wavelength of the light emitted is -5.49 x 1018 meters.