Question

A position vector of a 2 kg mass particle is given as a function of time by r = 6i + 5tj m/s. Determine the amount of angular movement of the particle around the origin, as a function of time.

a) 30t radians
b) 5t radians
c) 6 radians
d) 0 radians

Answer 1

The amount of angular movement of a particle around the origin is given by the equation θ = tan-1(5t/6) radians.

Step-by-step explanation:

The amount of angular movement of a particle around the origin can be determined by finding the angle that the position vector makes with the positive x-axis. In this case, the position vector is given as r = 6i + 5tj m/s.

To find the angle, we can use the trigonometric relationship between the x-component and the magnitude of the position vector. The angle θ is given by θ = tan-1(y/x), where y is the y-component and x is the magnitude of the position vector.

So, the amount of angular movement is given by the equation θ = tan-1(5t/6) radians.