Final answer:
To determine the grams of water produced in the neutralization reaction between calcium hydroxide and hydrochloric acid, you can use stoichiometry to calculate. The balanced equation is Ca(OH)2 + 2HCl → CaCl2 + 2H2O. From the equation, 2 moles of water are produced for every mole of calcium hydroxide. First, calculate the moles of calcium hydroxide, then use the mole ratio to determine the moles of water, and finally convert moles of water to grams.
Step-by-step explanation:
To determine the grams of water produced in the neutralization reaction between calcium hydroxide and hydrochloric acid, we need to calculate using stoichiometry.
The balanced chemical equation for the reaction is:
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
From the equation, we can see that for every mole of calcium hydroxide, 2 moles of water are produced. To calculate the grams of water, we need to determine the number of moles of calcium hydroxide and then use the mole ratio.
First, we can calculate the number of moles of calcium hydroxide using its molar mass:
100.0 g Ca(OH)2 x (1 mol Ca(OH)2 / 74.09 g Ca(OH)2) = 1.35 mol Ca(OH)2
Using the mole ratio from the balanced equation, we can determine the number of moles of water produced:
1.35 mol Ca(OH)2 x (2 mol H2O / 1 mol Ca(OH)2) = 2.70 mol H2O
Finally, we can convert the moles of water to grams using its molar mass:
2.70 mol H2O x (18.02 g H2O / 1 mol H2O) = 48.7 g H2O