Question

The orbital period of a satellite is 2 × 10⁶ seconds, and its tail radius is 2.5 × 10¹² meters. What is the tangential speed of a satellite?

a) 2 π × 10⁶/2.5 × 10¹² m/s

b) 2.5 × 10¹²/2 π × 10⁶ m/s

c) 2 π × 10¹²/2 × 10⁶ m/s

d) 2 × 10⁶/2.5 × 10¹² π m/s

Answer 1

The tangential speed of the satellite is 2π × 10⁶/2.5 × 10¹² m/s.

Step-by-step explanation:

The tangential speed of a satellite can be calculated using the formula:

vorbit = 2πr/T

where vorbit is the tangential speed, r is the radius of the orbit, and T is the orbital period. From the given information, we have a period of 2 × 10⁶ seconds and a radius of 2.5 × 10¹² meters.

Substituting these values into the formula:

vorbit = (2π × (2.5 × 10¹²))/(2 × 10⁶) = 2π × 10⁶/2.5 × 10¹² m/s