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Urn 1 contains 2 red balls and 2 white balls. Urn 2 contains 6 white balls. A ball is selected at random from urn 1 and placed in urn 2. What is the probability that the second ball selected from urn 2 is white?

A) (1/3)

B) (1/2)

C) (2/3)

D) (3/4)

User Polemarch
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1 Answer

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Final answer:

The probability that the second ball selected from urn 2 is white is 2/7.

Step-by-step explanation:

To find the probability that the second ball selected from urn 2 is white, we need to consider all possible outcomes. After taking one ball from urn 1 and transferring it to urn 2, the total number of balls in urn 2 is now 7, with 2 of them being white. So, the probability of selecting a white ball from urn 2 on the second draw is:

of ballsP(white on 2nd draw) = Number of white balls / Total number

P(white on 2nd draw) = 2 / 7 = 2/7

Therefore, the probability that the second ball selected from urn 2 is white is 2/7.

User CynicalSection
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