Final answer:
Yes, the subspace Y=[0,1]×[0,1) of the real plane R² is compact.
Step-by-step explanation:
Yes, the subspace Y=[0,1]×[0,1) of the real plane R² is compact.
To show that Y is compact, we can use the Heine-Borel theorem, which states that a subspace in R² is compact if and only if it is closed and bounded.
In this case, Y is bounded because the values of x are between 0 and 1, and the values of y are between 0 and 1 (excluding 1). Y is also closed because it includes its boundary [0,1]×{0}.