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Use implicit differentiation to find dy/dx for the lemniscate: (x² + y²)² = x² - y²

User Kholofelo
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Final answer:

To find dy/dx for the lemniscate, we use implicit differentiation and solve for dy/dx to get the result dy/dx = ⁄[2x - 4x(x² + y²)][4y(x² + y²) + 2y].

Step-by-step explanation:

To find dy/dx for the lemniscate given by the equation (x² + y²)² = x² - y², we apply implicit differentiation with respect to x. Differentiating each side of the equation, we get 2(x² + y²)(2x + 2ydy/dx) = 2x - 2ydy/dx. Now, solving for dy/dx, we combine like terms and isolate dy/dx.

Let's carry out the differentiation:

  • 2(x² + y²)(2x + 2ydy/dx) = 2x - 2ydy/dx,
  • 4x(x² + y²) + 4y(x² + y²)dy/dx = 2x - 2ydy/dx,
  • 4y(x² + y²)dy/dx + 2ydy/dx = 2x - 4x(x² + y²),
  • dy/dx(4y(x² + y²) + 2y) = 2x - 4x(x² + y²).

Finally, solving for dy/dx:

dy/dx = ⁄[2x - 4x(x² + y²)][4y(x² + y²) + 2y].

User Daniel Storey
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