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What is the solution of the linear quadratic system or equations?
a. Y=x²+5x-3
b. Y-x=2

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Final answer:

The solution to a linear quadratic system of equations is found using the substitution method, where one of the equations is solved for one variable and then substituted into the other equation.

Step-by-step explanation:

The student asked about the solution to a linear quadratic system of equations:

  1. y = x² + 5x - 3
  2. y - x = 2

To solve this system, we can use the substitution method. Firstly, we isolate y in the second equation:

y = x + 2

We then substitute this expression for y into the first equation:

x + 2 = x² + 5x - 3

Next, we rearrange the equation to form a quadratic equation:

x² + 5x - 3 - x - 2 = 0

x² + 4x - 5 = 0

Now, we need to find the roots of the quadratic equation, which can be solved by factoring, completing the square, or using the quadratic formula. Once we find the x-values, we can substitute them back into y = x + 2 to find the corresponding y-values, giving us the solution(s) to the system.

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