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If 25.5 mol of an ideal gas is at 4.05 x 10⁵ pa and 499 k, what is the volume v of the gas

1 Answer

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Answer:

V = 261 liters to 3 sig figs

Step-by-step explanation:

Use the ideal gas law:

PV = nRT

We'll use a gas constant, R, of 0.0821 L*atm/K*mol

That means we need to convert Pa into atm.

(4.05x10^5 Pa)*(1 atm/(101,325 Pa) = 4.00 atm

n = 25.5 moles

T = 499K

Rearrange to find V, the volume:

PV = nRT

V = (nRT)/P

Enter the data:

V = (nRT)/P

V = (25.5 mole)*( 0.0821 L*atm/K*mol)*(499K)/(4.00 atm)

Moles, temperature and atm all cancel, leaving just volume, in liters.

V = (25.5)*( 0.0821 L)*(499)/(4.00)

V = 261 liters to 3 sig figs

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