Final answer:
To heat 20 g of water from 52°C to the boiling point, which is 100°C, one must add 4018.4 Joules of heat, using the specific heat capacity of water and the formula for heat energy.
Step-by-step explanation:
Calculating Heat to Boil Water
To determine how much heat must be added to 20 g of water at an initial temperature of 52°C to bring it to the boiling point, we use the formula Q = mcΔT, where:
• ‘Q’ is the heat energy in Joules,
• ‘m’ is the mass of the water in kilograms,
• ‘c’ is the specific heat capacity of water (4.18 J/g°C), and
• ΔT is the change in temperature in degrees Celsius.
The boiling point of water is 100°C, so the change in temperature (ΔT) from 52°C to 100°C is 48°C. The mass of the water (m) is 20 grams, which we convert to kilograms by dividing by 1000, resulting in 0.020 kg. Substituting these values into the formula gives Q = 0.020 kg × 4.18 J/g°C × 48°C = 4018.4 J. Thus, 4018.4 Joules of heat must be added to 20 g of water to heat it from 52°C to the boiling point.