Final answer:
The initial kinetic energy of an alpha particle with an initial value of 7.56 MeV is 1.2112 × 10-12 J when converted from MeV to joules utilizing the conversion factor of 1 MeV = 1.6022 × 10-13 joules.
Step-by-step explanation:
The student is asking for the initial kinetic energy of an alpha particle expressed in joules when the given value is in megaelectron-volts (MeV). To convert this energy from MeV to joules, one must use the conversion factor where 1 MeV is equivalent to 1.6022 × 10-13 joules. Therefore, the initial kinetic energy of an alpha particle with an initial kinetic energy of 7.56 MeV can be calculated as follows:
KE (in joules) = 7.56 MeV × 1.6022 × 10-13 J/MeV = 1.2112 × 10-12 J.
This result gives us the kinetic energy in joules, which is a fundamental concept in physics, particularly in the study of nuclear physics and particle energetics.