Question

Two buckets, each with a different volume of water, start leaking water at the same time, but at different rates. assume the volumes are changing linearly. bucket volume (ml) time (min)110bucket a2,9002,000bucket b2,7252,050 how many minutes will it take before both buckets have the same volume of water in them? do not include units in your answer.

Answer 1

To find how long it will take before both buckets have the same volume of water, we need to determine the rates of change for each bucket. The rate of change is the change in volume divided by the change in time. It will take approximately 0.75 minutes for both buckets to have the same volume of water.

Step-by-step explanation:

To find how long it will take before both buckets have the same volume of water, we need to determine the rates of change for each bucket. The rate of change is the change in volume divided by the change in time.

For Bucket A: Rate of change = (2,900 mL - 2,000 mL) / (2 min - 0 min) = 900 mL/min

For Bucket B: Rate of change = (2,725 mL - 2,050 mL) / (2,050 min - 0 min) = 675 mL/min

Now, we can set up the equation:

900 mL/min * t min = 675 mL/min * t min,

where t represents the time in minutes. Solving for t, we get:

t = 675 / 900 = 0.75

Therefore, it will take approximately 0.75 minutes for both buckets to have the same volume of water.