Final answer:
In metaphase I of meiosis, with a diploid number of 16 (2n=16), there would be a total of 32 sister chromatids, as each of the 16 chromosomes consists of 2 sister chromatids.option d.
Step-by-step explanation:
The question '2n=16. How many sister chromatids are there during metaphase 1?' relates to meiosis, a type of cell division that reduces the chromosome number by half in gamete cells. Since metaphase I pertains to meiosis, and given that 2n=16 (where 'n' represents the haploid number), this means that in a diploid cell, there are 16 chromosomes. During metaphase I of meiosis, chromosomes line up as homologous pairs at the metaphase plate. Each chromosome in the pair consists of two chromatids. Thus, for a cell with a diploid number of 16, there would be 16 homologous pairs of chromosomes and each chromosome would consist of 2 sister chromatids, resulting in 32 sister chromatids in total during metaphase I.
During metaphase I of meiosis, sister chromatids line up at the metaphase plate. Each chromosome consists of two sister chromatids held together by a centromere. The total number of sister chromatids is determined by the number of chromosomes in the cell. In this case, the equation 2n=16 tells us that there are 16 chromatids. Since each chromosome has two sister chromatids, we divide 16 by 2 to get the total number of chromosomes, which is 8.