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What is the pH of a 0.24 M diethylamine solution? Kb = 8.6 x 10⁻4

a) pH = 1.68
b) pH = 3.42
c) pH = 11.58
d) pH = 7.0

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Final answer:

The pH of a 0.24 M diethylamine solution can be calculated using the Henderson-Hasselbalch equation. The approximate pH value is 3.42. The correct option is (b).

Step-by-step explanation:

The pH of a solution can be calculated using the concentration of the weak base and the equilibrium constant (Kb) for the base. In this case, the diethylamine solution has a concentration of 0.24 M and a Kb value of 8.6 x 10-4. Using the Henderson-Hasselbalch equation, we can calculate the pH:

pH = pKa + log([A-]/[HA])

The pKa can be calculated using the equation: pKa = -log(Ka), where Ka is the equilibrium constant for the conjugate acid.

Since diethylamine is a weak base, its conjugate acid is very weak. Therefore, we can approximate the pKa to be equal to the pKb (since pKa + pKb = 14).

Now, let's substitute the values into the equation:

pH = 14 - log(Kb) - log([A-]/[HA])

We can assume that the diethylamine is completely ionized, so [A-] will be equal to the initial concentration of the diethylamine (0.24 M). [HA] will be zero since it is the concentration of the conjugate acid, which we assume to be negligible.

pH = 14 - log(8.6 x 10-4) - log(0.24/0)

pH = 14 - log(8.6 x 10-4)

pH ≈ 3.42

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