Final answer:
At the depth of 10 meters, the pressure exerted by water is approximately 98 kPa, calculated using the formula P = hρg.
Step-by-step explanation:
The density of water is approximately 1 g/cm³, which also translates to 1000 kg/m³. The pressure exerted by a fluid at a specific depth can be calculated using the formula P = hρg, where P is the pressure, h is the depth of the fluid, ρ is the density of the fluid, and g is the acceleration due to gravity. Assuming the acceleration due to gravity is 9.81 m/s², the pressure at a depth of 10 meters can be calculated as follows:
P = (10 m) × (1000 kg/m³) × (9.81 m/s²) = 98100 Pa ≈ 98 kPa
Therefore, at a depth of 10 meters, the pressure exerted by water is approximately 98 kPa. Note that this calculation assumes standard Earth gravity and water being incompressible over this depth.