Final answer:
Marta's second square has an area four times larger than the first square because when side lengths are doubled, the area increases by a factor of four (since area is calculated by squaring the side length).
Step-by-step explanation:
The original question asks whether a rectangle and a parallelogram have the same area and then segues into a different, but related question about the area of squares. To assess the area of the squares mentioned, if Marta has one square with side length of 4 inches, and another square with each side being twice the length of the first, the area of the larger square will be four times the area of the smaller square. This is because area is calculated as side length squared for a square (A = s²), so if the side length is doubled (from 4 inches to 8 inches), the area will be 4² = 16 and 8² = 64 square inches, respectively. Therefore, the ratio of the areas is 64:16, which simplifies to 4:1, indicating the second square has an area four times larger than that of the first square.