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Given P(A) = 0.13, P(B) = 0.02, and P(A or B) = 0.15, are events A and B mutually exclusive?

a) Yes

b) No

User Sambo Kim
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1 Answer

2 votes

Final answer:

No, they are not, because P(B) and P(A) multiplied together are not equal to P(B AND A).

Step-by-step explanation:

No, they are not, because P(B AND A) = .585.

P(B)P(A) = (.65)(.65) = .423

.423 * .585 = P(B AND A)

So, P(B AND A) is not equal to P(B)P(A).

User Sayem Siam
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