Answer:
1.37 × 10²³ formula units MgCl₂
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
[Given] 21.6 g MgCl₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Mg - 24.31 g/mol
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of MgCl₂ - 24.31 + 2(35.45) = 95.21 g/mol
Step 3: Convert
- [DA] Set up:
![\displaystyle 21.6 \ g \ MgCl_2((1 \ mol \ MgCl_2)/(95.21 \ g \ MgCl_2))((6.022 \cdot 10^(23) \ formula \ units \ MgCl_2)/(1 \ mol \ MgCl_2))](https://img.qammunity.org/2022/formulas/chemistry/college/h6j7flx8zm675offdyhomaws1gxh2nkhxb.png)
- [DA] Multiply/Divide [Cancel out units]:
![\displaystyle 1.36619 \cdot 10^(23) \ formula \ units \ MgCl_2](https://img.qammunity.org/2022/formulas/chemistry/college/suzz4kjg8sekf56fttvpfzou4xnilid38v.png)
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.36619 × 10²³ formula units MgCl₂ ≈ 1.37 × 10²³ formula units MgCl₂