Question

Find the equation of the line perpendicular to 5x-5y=7 passing through (0, -4).

A.Y=−1/3x+4
B.Y=−1/3x−4
C.Y=−3x−4
D. Y=1/3x−4

Answer 1

To find the equation of a line perpendicular to 5x-5y=7 passing through (0, -4), the equation is y = -1/3x - 4. Hence the correct answer is option A

Step-by-step explanation:

To find the equation of a line perpendicular to 5x-5y=7 passing through (0, -4), we need to determine the slope of the given line. The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. By rearranging the given equation, we have -5y = -5x + 7, which can be simplified to y = x - 7/5. Since the slope of the given line is 1, the slope of any line perpendicular to it will be -1. Therefore, the equation of the line perpendicular to 5x-5y=7 passing through (0, -4) is y = -1/3x - 4. Therefore, the correct answer is B. Y = -1/3x - 4.

Hence the correct answer is option A