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If 54x²y³ = 3x+y√2x, what is the value of n?

a) 0

b) 4

c) 2

d) 3

User Flgn
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1 Answer

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Final answer:

To find the value of n in the equation 54x²y³ = 3x+y√2x, we compare the powers of x and y on both sides. The value of n is 0, as there is no single value of n that satisfies the equation.

Step-by-step explanation:

To find the value of n in the equation 54x²y³ = 3x+y√2x, we need to compare the powers of x and y on both sides of the equation.

On the left side of the equation, we have x² and y³, which means that n = 2 and n = 3 for x and y respectively.

On the right side of the equation, we have 3x+y√2x. In this expression, the power of x is 1 and the power of y is 0. Therefore, the value of n is 1 for x and 0 for y.

Since n is different for x and y on both sides of the equation, there is no single value of n that satisfies the equation. Therefore, the answer is (a) 0.

User ZimGil
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