Question

Complete the recursive formula of g(n)=25−49(n−1).

A. g(n)=g(n−1)−49
B. g(n)=25−49g(n−1)
C. g(n)=g(n−1)+49
D. g(n)=25+49g(n−1)

Answer 1

The correct completion of the recursive formula g(n)=25-49(n-1) is g(n)=g(n-1)-49, which reflects subtracting 49 from the previous term.

Step-by-step explanation:

To complete the recursive formula of g(n)=25−49(n−1), we first need to look at how g(n) is defined for a given n. In the context of recursion, we are expressing g(n) in terms of g(n−1). This makes it dependent on the previous term in the sequence. Since we are subtracting 49 for each subsequent term (as we go from n to n-1), the correct recursive formula is g(n)=g(n−1)−49. This formula indicates that to get the term g(n), we take the previous term g(n-1) and subtract 49.