Question

((3x-4)^°) and ((4x-1)^°) find the degree measure of each angle of the parallelogram.

a) ( (3x-4)^°, (4x-1)^°, (3x-4)^°, (4x-1)^° )
b) ( (3x-4)^°, (4x-1)^°, (180-(3x-4)^°), (180-(4x-1)^°) )
c) ( (3x-4)^°, (4x-1)^°, (180+(3x-4)^°), (180+(4x-1)^°) )
d) ( (180-(3x-4)^°), (180-(4x-1)^°), (3x-4)^°, (4x-1)^° )

Answer 1

The degree measure of each angle of the parallelogram is approximately 89.1° and 126.8°.

Step-by-step explanation:

The sum of the angles of a parallelogram is always 360 degrees. In this case, the given angles are ((3x-4)°) and ((4x-1)°).

Since the opposite angles of a parallelogram are congruent, we can set up an equation:

• ((3x-4)°) + ((4x-1)°) + ((3x-4)°) + ((4x-1)°) = 360°

Simplifying the equation, we get:

• 6x - 10° + 6x - 10° = 360°
• 12x - 20° = 360°
• 12x = 380°
• x = 31.7°

Now we can substitute the value of x back into the angles to find their measure:

• ((3x-4)°) = ((3(31.7)-4)°) = 89.1°
• ((4x-1)°) = ((4(31.7)-1)°) = 126.8°

Therefore, the degree measure of each angle of the parallelogram is approximately 89.1° and 126.8°.