Question

An excited hydrogen atom emits light with a wavelength of 397.2nm to reach the energy level for which n=2. What is the corresponding energy level?

a. n=1
b. n=2
c. n=3
d. n=4

Answer 1

The corresponding energy level for a wavelength of 397.2 nm in an excited hydrogen atom is n = 4.

Step-by-step explanation:

To determine the energy level corresponding to a wavelength of 397.2 nm, we can use the formula: E = -13.6 eV / n^2, where E is the energy level and n is the principal quantum number. We can rearrange the formula to solve for n: n = sqrt(-13.6 eV / E). Plugging in the given values, we get n ≈ sqrt(-13.6 eV / -3.4 eV) ≈ 4.

Therefore, the corresponding energy level for a wavelength of 397.2 nm is n = 4. So, the answer is d. n = 4.

To determine the energy level corresponding to a wavelength of 397.2 nm, we can use the formula: E = -13.6 eV / n^2, where E is the energy level and n is the principal quantum number. We can rearrange the formula to solve for n: n = sqrt(-13.6 eV / E). Plugging in the given values, we get n ≈ sqrt(-13.6 eV / -3.4 eV) ≈ 4.