Final answer:
The mass of silver present in 100 cm³ of a 1 mol/dm³ silver nitrate solution is a) 107 g
Step-by-step explanation:
The mass of silver present in 100 cm³ of a 1 mol/dm³ solution of silver nitrate (AgNO₃) can be calculated using the formula:
Mass = Volume x Concentration x Molar mass
First, we need to find the concentration of silver nitrate in mol/dm³ .
Since 1 dm³ is equal to 1000 cm³ , we divide the given concentration of 1 mol/dm³ by 1000 to get the concentration in mol/cm³, which is 0.001 mol/cm³
The molar mass of AgNO₃ is the sum of the atomic masses of silver (Ag), nitrogen (N), and three oxygen (O) atoms, which is 107.87 g/mol.
Now we can calculate the mass:
Mass = 100 cm³ x 0.001 mol/cm³ x 107.87 g/mol = 107.87 g
Therefore, the correct answer is a) 107 g. The mass of silver present in 100 cm³ of a 1 mol/dm³ silver nitrate solution is 107 g