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A triangle ABC has A(1,-4) B(3,-1) C(3,-8).Find the length of the sides AB and AC

1 Answer

2 votes

Answer:

Explanation:

AB=
\sqrt{(1^(2) -3^(2))+((-4)^(2) -(-1)^(2) ) }

=
√(7)

AC=
\sqrt{(3^(2) -1^(2) )+((-8)^(2)- (-4)^(2) )} \\

=
√(56)

User Ade Miller
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